IPL 2020, Match 43: Kings XI Punjab vs SunRisers Hyderabad - Toss Report
Published - 24 Oct 2020, 08:33 PM | Updated - 23 Aug 2024, 12:36 AM
High-flying Kings XI Punjab will be eyeing another scalp when they take on fellow playoffs hopeful SunRisers Hyderabad in the 43rd match of the Indian Premier League (IPL) 2020.
Kings XI Punjab’s chances of making it to the playoffs was looking done and dusted after they had managed to win only one of their opening seven games. However, the Punjab-based outfit has revived its chances by winning the previous three games.
What will boost their confidence even more is the fact that they beat the top three sides of the ongoing competition – Mumbai Indians, Royal Challengers Bangalore and Delhi Capitals – in their last three outings. With four wins from ten games, Kings XI Punjab are currently at the sixth spot in the points table.
SunRisers Hyderabad, on the other hand, are at the fifth spot on the points table with 4 wins from ten games. They have the winning momentum too after the impressive 8-wicket win over Rajasthan Royals in their previous outing. Neither of the two teams could afford any further slipup and one can expect a cracking game tonight.
Toss report:
SunRisers Hyderabad have won the toss and have opted to bowl first against Kings XI Punjab.
Playing elevens:
Kings XI Punjab:
KL Rahul(w/c), Mandeep Singh, Chris Gayle, Nicholas Pooran, Glenn Maxwell, Deepak Hooda, Murugan Ashwin, Chris Jordan, Mohammed Shami, Ravi Bishnoi, Arshdeep Singh
Sunrisers Hyderabad:
David Warner(c), Jonny Bairstow(w), Priyam Garg, Manish Pandey, Vijay Shankar, Abdul Samad, Jason Holder, Rashid Khan, Khaleel Ahmed, Sandeep Sharma, T Natarajan
Tagged:
IPL 2020 Kings XI Punjab (KXIP) Sunrisers Hyderabad (SRH) Toss Toss Report
